Should we deduct the loss of capacitor energy storage

Can you store energy in a capacitor from a voltage source?

On the other hand, if you chose to store energy in an inductor from a voltage source, then you would do so much more efficiently. But, if you store energy in a capacitor from a ramping voltage source (for instance a constant current source), the energy lost is near-enough zero.

What happens when a capacitor is charged from zero to a voltage?

When a capacitor is charged from zero to some final voltage by the use of a voltage source, the above energy loss occurs in the resistive part of the circuit, and for this reason the voltage source then has to provide both the energy finally stored in the capacitor and also the energy lost by dissipation during the charging process.

How much energy is lost when a capacitor is fully charged?

By the time the capacitor is fully charged, the cell has supplied QV Q V energy while the potential energy of the capacitor is QV/2 Q V / 2. So there is a net loss of QV/2 Q V / 2 joules of energy. Where is the energy lost? Since it is an ideal circuit, there is no resistance and there should be no heat loss.

What happens if you store energy in a capacitor?

But, if you store energy in a capacitor from a ramping voltage source (for instance a constant current source), the energy lost is near-enough zero. And, if you tried to store energy in an inductor using a current source, you would lose half the energy (and be faced with a massive voltage spike).

What if you charge a capacitor from a voltage source?

But, you could also factor in the method of putting energy into the capacitor or inductor. For instance, if you charged a capacitor from a voltage source, you would immediately lose 50% of the energy (a pulse of "infinite" current would also flow theoretically).

What happens if an uncharged capacitor is associated with a battery?

When an uncharged capacitor is associated with a battery then 50% of energy delivered by the battery is stored in the capacitor and the remaining 50% will be lost. Energy loss does not depend on the resistance of the circuit. Note: When initially capacitor is charged then heat loss is not equal to 21C V 2, find heat loss by use of following concept