The inductor suddenly disconnects after storing energy

How do inductors store energy?

I know inductors store energy in their magnetic field, generated by current flowing through them. What if you wired an inductor in series with a power source, load, and switch and allowed the current to freely flow. Now suddenly you open the switch, what happens?

What if an inductor is connected to a source?

Suppose an inductor is connected to a source and then the source is disconnected. The inductor will have energy stored in the form of magnetic field. But there is no way/path to discharge this energy? Short answer: It will find a way/path to discharge this energy. Longer answer:

What happens if you disconnect an inductor?

Thus, when you disconnect the inductor, the current changes from whatever it was to 0 in a very short amount of time. The resulting di dt d i d t becomes very large making the induced voltage very large. The formula has a - in front of it to indicate that it's in the opposite direction.It is a minor matter however.

What happens if an inductor is suddenly open circuited?

Physics Stack Exchange What happens when the circuit for an inductor is suddenly open circuited? A current through an inductor cannot change abruptly, so what happens if I have an inductor with current passing through, and I suddenly open circuit it so that no current flows through? You get an arc (hence the diodes protecting solenoids).

How does an inductor work?

For some milliseconds the current continues to flow across the already opened switch, passing through the ionized air of the spark. The energy stored in the inductor is dissipated in this spark. Summary: An inductor doesn't "want" the current to be interrupted and therefore induces a voltage high enough to make the current continuing.

What happens if a current passes through an inductor?

A current through an inductor cannot change abruptly, so what happens if I have an inductor with current passing through, and I suddenly open circuit it so that no current flows through? You get an arc (hence the diodes protecting solenoids). I believe the circuit technically explodes in this case. di t dt v ( t) = L